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putnam-competition

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valorisa / Putnam_B6_2011

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Solution complète du problème B6 du concours Putnam 2011 — le problème où pas 1 des 3407 candidats a marqué, ne serait-ce, qu'un seul point. Démonstration via l'exponentielle tronquée, racines doubles sur les corps finis et construction auxiliaire G(x) = F(x) - x + x^p.

algebra proof mathematics arithmetic polynomial modular-arithmetic finite-fields combinatorics problem-solving group-theory number-theory math-olympiad wilson-theorem exponential-function putnam competition-math fermat-little-theorem putnam-competition putnam-2011 undergraduate-math
  • Updated May 10, 2026
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