completed backtracking 3 - #1279
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Pull request overview
Adds two Java solutions for backtracking-related LeetCode problems (Subsets and Palindrome Partitioning) into the repository as standalone source files.
Changes:
- Added an iterative subset generation solution (
Subsets.java). - Added a backtracking palindrome partitioning solution (
palindromepartition.java).
Reviewed changes
Copilot reviewed 2 out of 2 changed files in this pull request and generated 3 comments.
| File | Description |
|---|---|
| Subsets.java | Adds an iterative power-set (subsets) implementation. |
| palindromepartition.java | Adds a recursive backtracking palindrome partitioning implementation. |
Suppressed comments (2)
Subsets.java:6
- Both Subsets.java and palindromepartition.java currently declare a top-level
class Solutionin the default package. If these files are compiled together, this will fail with a duplicate class definition. Consider renaming the class to match the file/problem so each top-level class name is unique in the project.
class Solution {
palindromepartition.java:6
- This declares another top-level
class Solutionin the default package, which conflicts with theSolutionclass in Subsets.java when compiled together. Rename this class to a unique name (ideally matching the problem/file) to avoid duplicate class errors.
class Solution {
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| // Time Complexity : O(2^n) where n is the number of elements in the input array. This is because for each element, we have two choices: include it in a subset or exclude it. | ||
| // Space Complexity : O(n) where n is the number of elements in the input array. This is the space required to store all possible subsets. |
| // Any problem you faced while coding this : Understanding the backtracking approach for generating all possible partitions. | ||
| // Your code here along with comments explaining your approach : used backtracking to generate all possible partitions of the input string. For each substring, we check if it is a palindrome. If it is, we add it to the current path and recursively call the helper function with the remaining substring. When we reach the end of the string, we add the current path to the result list. | ||
| class Solution { | ||
| List<List<String>> result; |
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| // Time Complexity : O(2^n) where n is the length of the input string. This is because for each character in the string, we have two choices: either to include it in the current partition or not, leading to a binary tree of possibilities. | ||
| // Space Complexity : O(n) where n is the length of the input string. This is the space required to store the recursion stack and the resulting partitions. |
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