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Proof for mathd_algebra_513 - #46

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Proof for mathd_algebra_513#46
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Proven lemmas: 1/1

The goal is to prove that if real numbers a and b satisfy the linear system 3·a + 2·b = 5 and a + b = 2, then necessarily a = 1 and b = 1 (i.e., the unique solution is (1,1)). The proof is decomposed into two sub-goals: first derive ha : a = 1 from the two given equations, and then derive hb : b = 1 from the same equations. Both sub-goals have been solved: Lean uses the linarith tactic to eliminate variables and conclude each equality directly from h₀ and h₁. With ha and hb established, the final step bundles them into the conjunction a = 1 ∧ b = 1. So progress is complete: 2 out of 2 key sub-results are proven, and nothing remains. An interesting aspect is that while the system can be solved manually by simple elimination (e.g., subtracting 2·(a+b)=4 from 3a+2b=5 to get a=1), linarith automates this linear reasoning cleanly.

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