fix: which -s is an illegal option#12
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When I try to execute your program on WSL2 (Ubuntu 20.04), I get the following error: ``` Illegal option -s Usage: /usr/bin/which [-a] args ``` I replaced it with: ```bash if [[ -z "$(which perl)" ]]; then #... ```
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When I try to execute your program on WSL2 (Ubuntu 20.04), I get the following error:
I replaced it with: