I used the following method to submit tasks:public SparkJobResult startJob(String data, Map<String, String> params) throws SparkJobServerClientException.I set the parameter data, like this:input.string=20171202142711145423 20171202142722193966 hdfs://ip:9090/user/ethinkops/ p1512120681406_Auto_2 /home/ethinkops/.But I got the following error:
Cannot parse config: String: 1: Expecting end of input or a comma, got ':' (if you intended ':' to be part of a key or string value, try enclosing the key or value in double quotes, or you may be able to rename the file .properties rather than .conf).
When I use # as a string delimiter, I can only get the first parameter value immediately following "input.string =".
Looking forward for your reply, thank you!!!
I used the following method to submit tasks:public SparkJobResult startJob(String data, Map<String, String> params) throws SparkJobServerClientException.I set the parameter data, like this:input.string=20171202142711145423 20171202142722193966 hdfs://ip:9090/user/ethinkops/ p1512120681406_Auto_2 /home/ethinkops/.But I got the following error:
Cannot parse config: String: 1: Expecting end of input or a comma, got ':' (if you intended ':' to be part of a key or string value, try enclosing the key or value in double quotes, or you may be able to rename the file .properties rather than .conf).
When I use # as a string delimiter, I can only get the first parameter value immediately following "input.string =".
Looking forward for your reply, thank you!!!