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grepl often faster with perl = T #51

@KyleHaynes

Description

@KyleHaynes

I notice this library has quite a few grepl calls. Not sure if you're aware but using perl is often considerably faster ...

example

> vec <- c(" ", "    ", "asdas", "dsdsd", letters, LETTERS)
> vec <- sample(vec, 10000000, replace = T)
> system.time(grepl("^\\s*$", vec))
   user  system elapsed 
   1.38    0.00    1.39 
> system.time(grepl("^\\s*$", vec, perl = T))
   user  system elapsed 
   0.72    0.03    0.75 
> system.time(grepl("^\\s*$", vec))
   user  system elapsed 
   1.32    0.00    1.33 
> system.time(grepl("^\\s*$", vec, perl = T))
   user  system elapsed 
   0.69    0.00    0.69 

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