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4sum_58.java
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93 lines (72 loc) · 2.63 KB
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/*
58. 4Sum
Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target?
Find all unique quadruplets in the array which gives the sum of target.
Example
Given array S = {1 0 -1 0 -2 2}, and target = 0. A solution set is:
(-1, 0, 0, 1)
(-2, -1, 1, 2)
(-2, 0, 0, 2)
Notice
Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a ≤ b ≤ c ≤ d)
The solution set must not contain duplicate quadruplets.
*/
/*
EASY WRONG POINTS:
1. Sort array first of all.
2. Fixed n - 2 numbers and do 2-sum.
*/
public class Solution {
/**
* @param numbers: Give an array
* @param target: An integer
* @return: Find all unique quadruplets in the array which gives the sum of zero
*/
List<List<Integer>> res;
public List<List<Integer>> fourSum(int[] numbers, int target) {
// write your code here
res = new ArrayList();
if (numbers == null || numbers.length == 0) {
return res;
}
Arrays.sort(numbers);
for (int i = 0;i < numbers.length - 3;i ++) {
if (i > 0 && numbers[i] == numbers[i - 1]) {
continue;
}
for (int j = i + 1;j < numbers.length - 2;j ++) {
if (j > i + 1 && numbers[j] == numbers[j - 1]) {
continue;
}
int start = j + 1, end = numbers.length - 1;
while (start < end) {
int sum = numbers[i] + numbers[j] + numbers[start] + numbers[end];
if (sum == target) {
addResult(numbers[i], numbers[j], numbers[start], numbers[end]);
start ++;
while (start < end && numbers[start] == numbers[start - 1]) {
start ++;
}
end --;
while (start < end && numbers[end] == numbers[end + 1]) {
end --;
}
} else if (sum < target) {
start ++;
} else {
end --;
}
}
}
}
return res;
}
private void addResult(int a, int b, int c, int d) {
List<Integer> one_res = new ArrayList();
one_res.add(a);
one_res.add(b);
one_res.add(c);
one_res.add(d);
res.add(one_res);
}
}