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005_longest_palindromic_substring.java
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95 lines (79 loc) · 2.62 KB
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/* Solution 01: looping midpoint */
class Solution {
public String longestPalindrome(String s) {
if (s == null || s.length() == 0) {
return "";
}
String maxSubString = "";
for (int i = 0; i < s.length(); i++) {
String str= findLongestPalindrome(s, i, i + 1);
if (str != null && str.length() > maxSubString.length()) {
maxSubString = str;
}
str = findLongestPalindrome(s, i - 1, i + 1);
if (str != null && str.length() > maxSubString.length()) {
maxSubString = str;
}
}
return maxSubString;
}
private String findLongestPalindrome(String s, int start, int end) {
/* even length */
while (start >= 0 && end < s.length()) {
if (s.charAt(start) != s.charAt(end)) {
break;
}
start --;
end ++;
}
start ++;
end --;
return s.substring(start, end + 1);
}
}
/* Solution 02: Dynamic DP */
class Solution {
boolean[][] visited;
boolean[][] memo;
public String longestPalindrome(String s) {
if (s == null || s.length() == 0) {
return "";
}
visited = new boolean[s.length()][s.length()];
memo = new boolean[s.length()][s.length()];
for (int i = 0; i < s.length(); i++) {
for (int j = 0; j < s.length();j ++) {
visited[i][j] = false;
memo[i][j] = false;
}
}
String maxSubString = s.substring(0, 1);
for (int i = 0; i < s.length(); i++) {
for (int j = i - 1; j >= 0; j --) {
if (isPalindrome(s, j, i) && (i - j + 1) > maxSubString.length()) {
maxSubString = s.substring(j, i + 1);
}
}
}
return maxSubString;
}
private boolean isPalindrome(String s, int start, int end) {
if (start < 0 || start >= s.length() || end < 0 || end >= s.length() || start > end) {
return true;
}
if (visited[start][end]) {
return memo[start][end];
}
visited[start][end] = true;
if (start == end) {
memo[start][end] = true;
return true;
}
if (s.charAt(start) == s.charAt(end)) {
memo[start][end] = isPalindrome(s, start + 1, end - 1);
return memo[start][end];
}
memo[start][end] = false;
return memo[start][end];
}
}