Problem 1: 1. primitive data type; reference type 2. F 3. default case Problem 2: 1. player[0] == winner[0] && player[1] == winner[1] || player[0] == winner[1] && player[1] == winner[0] 2. player[0] == winner[0] || player[0] == winner[1] || player[1] == winner[0] || player[1] == winner[1] 3. playerSum += player[i]; 4. winnerSum += winner[i]; 5. Math.random() * 100 6. winningNumber / 10 7. winningNumber % 10 8. counter < digitSize 9. Integer.parseInt( digit ) 或者 digit.charAt(0) - 48 10. firstPrize(playerDigits, winningDigits)
Problem 1:
Problem 2:
player[0] == winner[1] && player[1] == winner[0]
player[1] == winner[0] || player[1] == winner[1]