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Handle ?eval code generation differently #26

@kangalio

Description

@kangalio

Problem

Currently, the code provided to the ?eval command is wrapped like this:

fn main() {
	println!("{:?}", {
		// CODE HERE
	});
}

This has a small issue; when the code evaluates to a value with a lifetime, the code fails to compile, for example:

fn main() {
	println!("{:?}", {
		let a = 42;
		&a
	});
}

That's because &a exits the scope we explicitly declared with {}, but its lifetime is bound to something within that scope (a).

This is slightly confusing for bot users and also a bit annoying.

How to fix

You may be able to prevent this issue by wrapping the code differently. The following ?eval input...

/* line 1 */;
/* line 2 */;
/* line 3 */;
/* line 4 */

...would be translated to the following Rust code...

fn main() {
	/* line 1 */;
	/* line 2 */;
	/* line 3 */;
	println!("{:?}", /* line 4 */);
}

In other words: the code will be split up by semicolons and only the result of the last line is put into the println!(). The rest are top-level statements inside main.

I'm not sure if there are edge cases in which this approach would break

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