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EWMA Questions #58

@willie-shen

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@willie-shen

I just wanted to ask, how do I go from

16y(t) = x(t) + 15y(t-1)

to

16y(t) = x(t) + 16y(t-1) - (16(y(t-1)-16/2)/16

My understanding is that if I apply the correction factor for rounding, wouldn't it be

16y(t) = x(t) + 15y(t-1) + 8

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