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ConvertBstToGreaterTree.py
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59 lines (44 loc) · 1.36 KB
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#!/usr/bin/env python
# -*- coding: utf-8 -*-
# @Time : 2019/10/31 23:39
# @Author : tc
# @File : ConvertBstToGreaterTree.py
"""
题号 538 把二叉搜索树转换为累加树
给定一个二叉搜索树(Binary Search Tree),把它转换成为累加树(Greater Tree),使得每个节点的值是原来的节点值加上所有大于它的节点值之和。
例如:
输入: 二叉搜索树:
5
/ \
2 13
输出: 转换为累加树:
18
/ \
20 13
二叉树的中序遍历是一个递增的数组,所以我们可以从尾部开始遍历,依次往左累加。这样遍历顺序就是右子树->根结点->左子树
"""
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution:
def convertBST(self, root: TreeNode) -> TreeNode:
if root:
self.dfs(root,0)
return root
def dfs(self,root, sum):
if not root:
return sum
sum = self.dfs(root.right,sum)
root.val += sum
sum = self.dfs(root.left,root.val)
return sum
if __name__ == '__main__':
node1 = TreeNode(5)
node2 = TreeNode(2)
node3 = TreeNode(13)
node1.left = node2
node1.right = node3
solution = Solution()
print(solution.convertBST(node1))