JSONObject.toJSON时未去解析注解的问题

[anigkus]

#Example

import com.alibaba.fastjson.JSONObject;
import com.alibaba.fastjson.annotation.JSONField;
import java.io.Serializable;
import lombok.AllArgsConstructor;
import lombok.Builder;
import lombok.NoArgsConstructor;

public class Test {

  @lombok.Data
  @NoArgsConstructor
  @AllArgsConstructor
  @Builder
  public static class Req implements Serializable {

    @JSONField(name = "method", defaultValue = "payStatus")
    private String method;

    @JSONField(name = "merchantCode")
    private String merchantCode;

    @JSONField(name = "data")
    private String data;
  }

  public static void main(String[] args) {
    Test.Req req = Test.Req.builder().merchantCode("b").data("c").build();
    String json = JSONObject.toJSONString(req);
    JSONObject jsonObject = (JSONObject) JSONObject.toJSON(req);
    System.out.println(json); //{"data":"c","merchantCode":"b","method":"payStatus"}
    System.out.println(jsonObject); //{"merchantCode":"b","data":"c"}
  }
}

已经在com.alibaba.fastjson.serializer.FieldSerializer#getPropertyValue方法中增加了逻辑，看你们觉得是否要合并下这块代码

if (propertyValue == null) {
            JSONField jsonField = fieldInfo.getAnnotation();
            if (jsonField != null && !"".equals(jsonField.defaultValue())) {
                propertyValue = jsonField.defaultValue();
            }
        }

相关补丁