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mex_repitition(math).cpp
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57 lines (47 loc) · 1.38 KB
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#include<bits/stdc++.h>
using namespace std;
#define faster_ayman ios_base::sync_with_stdio(false);cin.tie(NULL);
#define int long long
#define pb push_back
#define rep(i, a, b) for (auto i = a; i < b; i++)
#define all(a) (a).begin(), (a).end()
#define testcase int tt;cin >> tt;while (tt--)
#define inf 1e18
typedef vector<int> vi;
typedef vector<pair<int,int>> vp;
typedef vector<double> vd;
typedef vector<char> vc;
typedef set<int> si;
typedef set<char> sc;
typedef unordered_set<int> usi;
void solve() {
int n, k; cin >> n >> k;
vi a(n);
int mex_aager = (n * (n + 1)) / 2;
rep(i, 0, n) cin >> a[i], mex_aager -= a[i];
// int new_mex = 0;
// rep(i, 0, k) {
// rep(j, 0, n) {
// new_mex = a[j];
// a[j] = mex_aager;
// mex_aager = new_mex;
// }
// }
a.pb(mex_aager);
n++;
vi ans (n);
rep(i, 0, n) {
int pos = (i + k) % n;
ans[pos] = a[i];
}
ans.pop_back();
for (auto it : ans) cout << it << ' ';
cout << '\n';
}
signed main() {
faster_ayman
testcase {
solve();
}
return 0;
}