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InOrderRecursion.java
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80 lines (73 loc) · 1.85 KB
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package lintcode;
import DataStructure.TreeNode;
/**
* Created by KXC176 on 4/12/2017.
*
* 二叉树
*
* 中序遍历
*
* 对于当前结点,先输出它的左孩子,然后输出该结点,最后输出它的右孩子
*
* 1
* / \
* 2 3
* / /
* 4 5
* \
* 6
* \
* 7
*
* inorder output : 4 6 7 2 1 5 3
*
* 1
* / \
* 2 3
* / \ /
* 4 5 6
* / / \
* 7 8 9
*
* inorder output : 7 4 2 5 1 8 6 9 3
*
*/
public class InOrderRecursion {
public void InOrderRec(TreeNode root){
if (root == null){
return;
}
InOrderRec(root.left);
System.out.print(" "+root.val);
InOrderRec(root.right);
}
public static void main(String[] args) {
TreeNode node1 = new TreeNode(1);
TreeNode node2 = new TreeNode(2);
TreeNode node3 = new TreeNode(3);
TreeNode node4 = new TreeNode(4);
TreeNode node5 = new TreeNode(5);
TreeNode node6 = new TreeNode(6);
TreeNode node7 = new TreeNode(7);
TreeNode node8 = new TreeNode(8);
TreeNode node9 = new TreeNode(9);
// Tree 1
node1.left = node2;
node1.right = node3;
node3.left = node5;
node2.left = node4;
node4.right = node6;
node6.right = node7;
//Tree 2
// node1.left = node2;
// node1.right = node3;
// node2.left = node4;
// node2.right = node5;
// node4.left = node7;
// node3.left = node6;
// node6.left = node8;
// node6.right = node9;
InOrderRecursion inOrderRecursion = new InOrderRecursion();
inOrderRecursion.InOrderRec(node1);
}
}