From 434680650cfd0f300b7d2c4cc8823c64f865ee70 Mon Sep 17 00:00:00 2001
From: Christopher Liu <christopherliu830@gmail.com>
Date: Sun, 10 Jul 2016 18:33:14 -0400
Subject: [PATCH] Assignment 7

---
 assignment7.txt | 16 ++++++++++++++++
 reverse.c       | 21 +++++++++++++++++++++
 2 files changed, 37 insertions(+)
 create mode 100644 assignment7.txt
 create mode 100644 reverse.c

diff --git a/assignment7.txt b/assignment7.txt
new file mode 100644
index 0000000..d6d8872
--- /dev/null
+++ b/assignment7.txt
@@ -0,0 +1,16 @@
+1. For an array {1, 2, 3, 4}
+	a. ++*p will get the variable located at *p then increment it. if *p is at index 0, new array would be {2, 2, 3, 4} with *p at index 0
+	b. *p++ will increment p (move the index forward once), then get the value of it. If *p is at index 0, then the array will be {1,2,3,4} with *p at index 1
+	c. *++p is equivalent to *p++ as the prefix ++ and * evaluate right to left.
+2. No, it depends on the type of operator.
+3. Pointers are used for functions that need to actually change their arguments or for returning an array of values
+4.1 char[]
+4.2 invalid
+4.3 int 0
+4.4 int 10
+4.5 int * a
+4.6 int 12
+4.7 int ** 
+4.8 char *
+4.9 invalid
+4.10 unsigned long int 8
\ No newline at end of file
diff --git a/reverse.c b/reverse.c
new file mode 100644
index 0000000..3a582a3
--- /dev/null
+++ b/reverse.c
@@ -0,0 +1,21 @@
+/*Christopher Liu */
+#include <stdio.h>
+#include <string.h>
+
+int main()
+{
+	printf("String: ");
+	char string[100];
+	fgets(string, 100, stdin);
+
+	char *stringPtr = string;
+	char *end_stringPtr = &string[strlen(string)];
+
+	while (*stringPtr != *end_stringPtr)
+	{
+		printf("%c", *(--end_stringPtr));
+	}
+	printf("\n");
+
+	return 0;
+}